-y^2-y+28=0

Solution for -y^2-y+28=0 equation:

-y^2-y+28=0

We add all the numbers together, and all the variables

-1y^2-1y+28=0

a = -1; b = -1; c = +28;
Δ = b2-4ac
Δ = -12-4·(-1)·28
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{113}}{2*-1}=\frac{1-\sqrt{113}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{113}}{2*-1}=\frac{1+\sqrt{113}}{-2}
$